'Twas the Evening of Christmas

'Twas the Evening of Christmas

Matematika JAWAB BESERTA CARANYA PLISSS!!!

YANG JAGO MATEMATIKA AYO JANGAN NGASAL!!!​

JAWAB BESERTA CARANYA PLISSS!!!

YANG JAGO MATEMATIKA AYO JANGAN NGASAL!!!​

Tabung A:

V = π × r × r × t

= 3,14 × 4 × 4 × 10

= 50,24 × 10

= 502,4 cm³

Tabung B:

V = π × r × r × t

= 22/7 × 7 × 7 × 6

= 22 × 1 × 7 × 6

= 924 cm³

Tabung C:

V = π × r × r × t

= 3,14 × 1 × 1 × 8

= 25,12 cm³

Tabung D:

V = π × r × r × t

= 3,14 × 2 × 2 × 10

= 12,56 × 10

= 125,6 cm³

nomor a

Luas permukaan tabung = 2 × π × r × (r + t)

lp = 2 × 22/7 × 4 × (4 + 10)

lp = 2 × 22/7 × 4 × 14

lp = 2 × 22/1 × 4 × 2

lp = 44/1 × 4 × 2

lp = 44 × 4 × 2

lp = 176 × 2

lp = 352cm²

volume = π × r × r × t

v = 3,14 × 4 × 4 × 10

v = 12,56 × 4 × 10

v = 50,24 × 10

v = 502,4cm³

nomor b

luas permukaan tabung = 2 × π × r × (r + t)

lp = 2 × 22/7 × 7 × (7 + 6)

= 2 × 22/7 × 7 × 13

= 2 × 22/1 × 1 × 13

= 2 × 22 × 13

= 44 × 13

= 576cm²

volume = π × r × r × t

v = 22/7 × 7 × 7 × 6

= 22/1 × 1 × 7 × 6

= 22 × 42

= 924cm³

nomor c

r = d/2

= 2/2

= 1m

luas permukaan tabung = 2 × π × r × (r + t)

lp = 2 × 3,14 × 1 × (1 + 8)

lp = 6,28 × 1 × 9

lp = 6,28 × 9

lp = 56,52m²

volume tabung = π × r × r × t

v = 3,14 × 1 × 1 × 8

= 3,14 × 1 × 8

= 3,14 × 8

= 25,12cm³

nomor d

r = d/2

= 4/2

= 2

luas permukaan tabung = 2 × π × r × (r + t)

lp = 2 × 3,14 × 2 × (2 + 10)

= 6,28 × 2 × (2 + 10)

= 6,28 × 2 × 12

= 12,56 × 12

= 150,72cm²

volume tabung = π × r × r × t

v = 3,14 × 2 × 2 × 10

= 6,28 × 2 × 10

= 12,56 × 10

= 125,6cm³

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